a^2 + b^2 + c^2 = d^2 + e^2 + f^2

a^2=> ‘a’ raised to the power of 2

a,b,c,d,e,f => Integers from 1 to 9

Solve for {a,b,c,d,e,f}. Three such solution sets are possible!

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August 14, 2007 by ashwinc

a^2 + b^2 + c^2 = d^2 + e^2 + f^2

a^2=> ‘a’ raised to the power of 2

a,b,c,d,e,f => Integers from 1 to 9

Solve for {a,b,c,d,e,f}. Three such solution sets are possible!

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on August 20, 2007 at 10:35 am |kk/me is able to get two.. the third one stumps me…

on August 20, 2007 at 10:57 am |ashwincAll 3 solutions are…

1+36+64 = 4+16+81

4+36+49 = 9+16+64

1+16+81 = 9+25+64

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