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Find out the numbers…

August 14, 2007 · 2 Comments

a^2 + b^2 + c^2 = d^2 + e^2 + f^2

a^2=> ‘a’ raised to the power of 2
a,b,c,d,e,f => Integers from 1 to 9
Solve for {a,b,c,d,e,f}. Three such solution sets are possible!

Categories: Maths